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2013 May 8 7:53 AM

1-9 with 2d6

I read a thread about Dave Arneson’s First Fantasy Campaign right before I went to bed, and this is the first think that popped into my head when I woke up.

On a d6, assume that a roll of 1–2 = 1, 3–4 = 2, and 5–6 = 3. Roll 2d6, and multiply. This gives a flat result of 1–9.

EDIT: As pointed out in the comments, this is not flat at all. That’s what I get for posting while half asleep. As Dallas M on G+ pointed out, 3 * (1d3 - 1) + (1d3 - 1) + 1 produces the desired results. And his further formulation is even better:

Start with range 1–9. Roll 1d3: that chooses one of the subranges 1–3, 4–6 or 7–9. Roll 1d3: that chooses a result in the chosen subrange.


3 comments:

Jeremy Deram, May 8, 2013 at 8:28 AM

I have a bunch of these: http://www.amazon.com/gp/aw/d/B001EQT924

Brett Slocum, May 8, 2013 at 8:39 AM

It’s not a flat 1-9.

1 2 3
1 1 2 3
2 2 4 6
3 3 6 9

1, 2, 2, 3, 3, 4, 6, 6, 9

JDJarvis, May 8, 2013 at 2:03 PM

You can also do 1-4. 1-12, 1- 18, 1-36 with 2d6.

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